x^2-46x+8=0

Solution for x^2-46x+8=0 equation:

x^2-46x+8=0

a = 1; b = -46; c = +8;
Δ = b2-4ac
Δ = -462-4·1·8
Δ = 2084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2084}=\sqrt{4*521}=\sqrt{4}*\sqrt{521}=2\sqrt{521}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-2\sqrt{521}}{2*1}=\frac{46-2\sqrt{521}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+2\sqrt{521}}{2*1}=\frac{46+2\sqrt{521}}{2}
$